Question: The de Broglie wavelength associated with an electron, accelerated by a potential difference of 81 V is given by:

A) 13.6 nm

B) 136 nm

C) 1.36 nm

D) 0.136 nm

Answer: 0.136 nm

Solution:

λe=12.27VAo=12.2781Ao=12.279Ao =1.36Ao(1Ao=110 nm) =0.136 nm