NEET Solved Paper 2019 Question 5
Question: Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J] [NEET 5-5-2019]
Options:
A) 25 J
B) 30 J
C) -30 J
D) 5 Kj
Show Answer
Answer:
Correct Answer: C
Solution:
Thermodynamics $ W=P _{ext}\Delta V $ = -2(bar) (0.15 L) = -0.3 bar: = -0.3 × 100 J = - 30 J
