NEET Solved Paper 2019 Question 25
Question: For the cell reaction [NEET 5-5-2019]
$ 2F{e^{3+}}(aq)+2{I^{}}(aq)\to 2F{e^{2+}}(aq)+I _2(aq) $
$ E_cell^{\Theta }E=0.24Vat298K $ . The standard Gibbs energy $ ({\Delta_r}{G^{\Theta }}) $ of the cell reaction is: [Given that Faraday constant $ F=96500Cmol^{1} $ ]
Options:
A) $ 46.32kJmol^{1} $
B) $ 23.16kJmol^{1} $
C) $ -46.32kJmol^{1} $
D) $ -23.16kJmol^{1} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta G{}^\circ =-nF,E_cell^{\Theta } $
$ =2(96500),\text{(}0.24\text{)} $
$ =-46320J/mole $
$ =-\frac{46320}{1000} $
$ =-46.32KJ/mole $
