NEET Solved Paper 2016 Question 36
Question: The ratio of escape velocity at earth $ (v _{e}) $ to the escape velocity at a planet $ (v _{p}) $ whose radius and mean density are twice as that of earth is :-
Options:
A) 1 : 2
B) $ 1:2\sqrt{2} $
C) 1 : 4
D) $ 1:\sqrt{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ V _{e}=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2G}{R}.( \frac{4}{3}\pi R^{3}\rho )}\propto R\sqrt{\rho } $
$ \therefore $ $ Ratio\text{=}1:2\sqrt{2} $
