Neet Solved Paper 2015 Question 22
Question: The ratio of the specific heats $ \frac{C _{p}}{C _{v}}=\gamma $ in terms of degrees of freedom (n) is given by
Options:
A) $ ( 1+\frac{1}{n} ) $
B) $ ( 1+\frac{n}{3} ) $
C) $ ( 1+\frac{2}{n} ) $
D) $ ( 1+\frac{2}{n} ) $
Show Answer
Answer:
Correct Answer: C
Solution:
The specific heat of gas at constant volume in terms of degree of freedom n is
$ C _{v}=\frac{n}{2}R $ Also $ C _{p}-C _{v}=R $ So
$ C _{p}=\frac{n}{2}R+R=R( 1+\frac{n}{2} ) $ Now,
$ \gamma =\frac{C _{p}}{C _{v}}=\frac{R( 1+\frac{n}{2} )}{\frac{n}{2}R}=\frac{2}{n}+1 $
