Neet Solved Paper 2015 Question 28
Question: Which of the following statements is correct for a reversible process in a state of equilibrium?
Options:
A) $ \Delta G=-2.30RT,\log K $
B) $ \Delta G=2.30RT,\log K $
C) $ \Delta {G^{{}^\circ }}=-2.30RT,\log K $
D) $ \Delta {G^{{}^\circ }}=2.30RT,\log K $
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Answer:
Correct Answer: C
Solution:
Mathematical expression of the thermodynamic equilibrium is
$ \Delta G=\Delta {G^{o}},+2.303RTlogQ $ At equilibrium when $ \Delta G=0 $ and Q = K then
$ \Delta G=\Delta {G^{{}^\circ }}+2.303RT\log K=0 $ $ \Delta {G^{{}^\circ }}=-2.303RT\log K $
