Neet Solved Paper 2015 Question 24

Question: The number of d-electrons in $ F{e^{2+}},(Z=26) $ is not equal to the number of electrons in which one of the following?

Options:

A) s-electrons in $ Mg(Z=12) $

B) p-electrons in $ Cl(Z=17) $

C) d-electrons in $ Fe(Z=26) $

D) p-electrons in $ Ne(Z=10) $

Show Answer

Answer:

Correct Answer: B

Solution:

Electronic configuration of $ F{e^{2+}} $ is $ [Ar]3d^{6}4s^{0}. $

$ \therefore $ Number of electrons = 6 $ Mg-1s^{2}2s^{2}2p^{6}3s^{2} $ (6d electrons)

It matches with the 6d electrons of $ F{e^{2+}} $ $ Cl-1s^{2}2s^{2}2p^{6},3s^{2}3p^{5} $ (11p elections)

It does not match with the 6d electrons of $ F{e^{2+}} $ . $ Fe-[Ar]3d^{6}4s^{2} $ (6d electrons)

It matches with the 6d electrons of $ F{e^{2+}}. $ $ Ne-1s^{2}2s^{2}2p^{6} $ (6p electrons)

It matches with the 6d electrons of $ F{e^{2+}}. $

Hence, $ Cl $ has 11p electrons which does not matches in number with 6d electrons of $ F{e^{2+}}. $