NEET Solved Paper 2014 Question 3
Question: A particle is moving such that its position coordinates (x, y) are (2m, 3m) at time t = 0, (6m, 7m) at time t = 2 s and (13m, 14m) at time t = 5 s. Average velocity vector ( $ {\upsilon _{a\upsilon }} $ ) from t = 0 to t = 5 s is [AIPMT 2014]
Options:
A) $ \frac{1}{5}(13\mathbf{\hat{i}}+14\mathbf{\hat{j}}) $
B) $ \frac{7}{3}(\mathbf{\hat{i}}+\mathbf{\hat{j}}) $
C) $ 2(\mathbf{\hat{i}}+\mathbf{\hat{j}}). $
D) $ \frac{11}{5}(\mathbf{\hat{i}}+\mathbf{\hat{j}}) $
Show Answer
Answer:
Correct Answer: D
Solution:
Average velocity vector $ v _{av}=\frac{Net,displacement}{Time,taken} $
$ =\frac{(13-2)\hat{i}+(14-3)\hat{j}}{5} $
$ =\frac{11\hat{i}+11\hat{j}}{5}=\frac{11}{5}(\hat{i}+\hat{j}) $
