NEET Solved Paper 2014 Question 24
Question: A conducting sphere of radius R is given a charge Q. The electric potential and the electric field at the centre of the sphere respectively are [AIPMT 2014]
Options:
A) zero and $ \frac{Q}{4\pi {\varepsilon_0}R^{2}} $
B) $ \frac{Q}{4\pi {\varepsilon_0}R} $ and zero .
C) $ \frac{Q}{4\pi {\varepsilon_0}R} $ and $ \frac{Q}{4\pi {\varepsilon_0}R^{2}} $
D) Both are zero
Show Answer
Answer:
Correct Answer: B
Solution:
$ {E _{inside}}=0 $ and $ {V _{inside}}\text{=}{V _{surface}}=\frac{1}{4\pi {\varepsilon_0}}\frac{Q}{R} $
