NEET Solved Paper 2014 Question 18

Question: The pair of compounds that can exist together is [AIPMT 2014]

Options:

A) $ FeCl _3,SnCl _2 $

B) $ HgCl _2,SnCl _2 $

C) $ FeCl _2,SnCl _2 $

D) $ FeCl _3,Kl $

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Answer:

Correct Answer: C

Solution:

The compounds with lower oxidation number and which cannot reduced by one another can exist together.

Thus, $ FeCl _2 $ and $ SnCl _2 $ can exist together as $ F{e^{2+}} $ cannot be reduced by $ S{n^{2+}}. $