NEET Solved Paper 2014 Question 11
Question: The weight of silver (at. wt. = 108) displaced by a quantity of electricity which displaces 5600 mL of $ O _2 $ at STP will be [AIPMT 2014]
Options:
A) 5.4 g
B) 10.8 g
C) 54.0 g
D) 108.0 g
Show Answer
Answer:
Correct Answer: D
Solution:
Since, 22400 mL volume is occupied by 1 mole of $ O _2 $ at STP.
Thus, 5600 mL $ O _2 $ means = $ \frac{5600}{22400}molO _2 $ $ =\frac{1}{4}mol,O _2 $
$ \therefore $ Weight of $ O _2\frac{1}{4}\times 32=8g $ According to problem,
Equivalents of Ag = Equivalents of $ O _2 $ = $ \frac{~\text{ }~\text{ }~\text{ Weight of Ag}}{\text{Equivalent weight of Ag}} $ = $ \frac{{W_O} _{_2}}{Equivalent,weight,of,{O_2}} $ $ \frac{W _{Ag}}{\frac{M _{Ag}}{VF}}=\frac{{W _{O _2}}}{\frac{{M _{O _2}}}{VF}} $
$ \therefore $ $ \frac{W _{Ag}}{108}\times \frac{8}{32}\times 4 $ $ [\because ,2H _2O\to O _2+4{H^{+}}+4{e^{-}}] $
Þ $ W _{Ag}=108g $
