Work Energy and Power - Result Question 7

9. 300J of work is done in sliding a 2kg block up an inclined plane of height 10m. Taking g=10 m/s2, work done against friction is

[2006]

(a) 100J

(b) zero

(c) 1000J

(d) 200J

Show Answer

Answer:

Correct Answer: 9. (a)

Solution:

  1. (a) Work done against gravity =mgsin⁡θ×d (dsin⁡θ=10)

=2×10×10

=200J

Actual work done =300J

Work done against friction =300−200 =100J

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