SATHEE: Work Energy and Power - Result Question 68

Work Energy and Power - Result Question 68

71. A body of mass $5 k g$ explodes at rest into three fragments with masses in the ratio $1 : 1 : 3$ . The fragments with equal masses fly in mutually perpendicular directions with speeds of $21 m /$ $s$ . The velocity of heaviest fragment in $m / s$ will be

[1989]

(a) $7 \sqrt{2}$

(b) $5 \sqrt{2}$

(d) $\sqrt{2}$

Show Answer

Answer:

Correct Answer: 71. (a)

Solution:

(a) Momentum of Ist part $= m \times 21 = 21 m$

Momentum of 2nd part $= m \times 21 = 21 m$

Resultant momentum, $= \sqrt{(m 21)^{2} + (m 21)^{2}}$

Resultant momentum $=$ momentum of $3 r d$ part

$\Rightarrow 21 \sqrt{2} m = 3 m v$

$\Rightarrow v = 7 \sqrt{2} m / s e c$

Masses of the pieces are 1, 1,3 kg. Hence $(1 \times 21)^{2} + (1 \times 21)^{2} = (3 \times V)^{2}$

That is, $V = 7 \sqrt{2} m / s$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Work Energy and Power - Result Question 68

71. A body of mass 5kg explodes at rest into three fragments with masses in the ratio 1:1:3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21m/ s. The velocity of heaviest fragment in m/s will be

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

71. A body of mass $5 k g$ explodes at rest into three fragments with masses in the ratio $1 : 1 : 3$ . The fragments with equal masses fly in mutually perpendicular directions with speeds of $21 m /$ $s$ . The velocity of heaviest fragment in $m / s$ will be