Work Energy and Power - Result Question 45

48. A particle of mass 5m at rest suddenly breaks on its own into three fragments. Two fragments of mass m each move along mutually perpendicular direction with speed v each. The energy released during the process is,

[NEET Odisha 2019]

(a) 43mv2

(b) 35mv2

(c) 53mv2

(d) 32mv2

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Answer:

Correct Answer: 48. (a)

Solution:

  1. (a) From conservation of linear momentum.

0=mvj^+mvi^+3mv1 v1=v3(i^+j^) v1=23v Kf=12mv2+12mv2+12(3m)(23)2v2 =mv2+mv23=43mv2 ΔKE=KfKi=43mv2



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