SATHEE: Waves - Result Question 45

Waves - Result Question 45

47. The number of possible natural oscillation of air column in a pipe closed at one end of length $85 c m$ whose frequencies lie below $1250 H z$ are : (velocity of sound $= 340 m s^{- 1}$ ) [2014]

(a) 4

(b) 5

(d) 6

Show Answer

Answer:

Correct Answer: 47. (d)

Solution:

(d) In case of closed organ pipe frequency,

$f_{n} = (2 n + 1) \frac{v}{4 l}$

for $n = 0, f_{0} = 100 H z$

$n = 1, f_{1} = 300 H z$

$n = 2, f_{2} = 500 H z$

$n = 3, f_{3} = 700 H z$

$n = 4, f_{4} = 900 H z$

$n = 5, f_{5} = 1100 H z$

$n = 6, f_{6} = 1300 H z$

Hence possible natural oscillation whose frequencies $< 1250 H z = 6 (n = 0, 1, 2, 3, 4, 5)$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Waves - Result Question 45

47. The number of possible natural oscillation of air column in a pipe closed at one end of length 85cm whose frequencies lie below 1250Hz are : (velocity of sound =340ms−1 ) [2014]

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

47. The number of possible natural oscillation of air column in a pipe closed at one end of length $85 c m$ whose frequencies lie below $1250 H z$ are : (velocity of sound $= 340 m s^{- 1}$ ) [2014]