SATHEE: Waves - Result Question 31

Waves - Result Question 31

31. The frequency of sinusoidal wave $y = 0.40 \cos$ $[2000 t + 0.80]$ would be

[1992]

(a) $1000 π H z$

(b) $2000 H z$

(d) $\frac{1000}{π} H z$

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Answer:

Correct Answer: 31. (d)

Solution:

(d) Given $y = 0.40 \cos [2000 t + 0.80]$

Comparing with the standard equation

$y = A \cos (2 π v t + ϕ)$

We get angular frequency, $2 π ν = 2000$ $v \Rightarrow \frac{2000}{2 π} = \frac{1000}{π} H z$

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Waves - Result Question 31

31. The frequency of sinusoidal wave y=0.40cos [2000t+0.80] would be

Answer:

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31. The frequency of sinusoidal wave $y = 0.40 \cos$ $[2000 t + 0.80]$ would be