Wave Optics - Result Question 29

31. At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen’s wavelet from the edge of the slit and the wavelet from the midpoint of the slit is :

[2015 RS]

(a) $\frac{\pi}{2}$ radian

(b) $\pi$ radian

(c) $\frac{\pi}{8}$ radian

(d) $\frac{\pi}{4}$ radian

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Answer:

Correct Answer: 31. (b)

Solution:

  1. (b) For first minima at $P$

$AP-BP=\lambda$

$AP-MP=\frac{\lambda}{2}$

So phase difference, $\phi=\frac{2 \pi}{\lambda} \times \frac{\lambda}{2}=\pi$ radian



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