Wave Optics - Result Question 26
28. The ratio of resolving powers of an optical microscope for two wavelengths $\lambda_1=4000 \AA$ and $\lambda_2=6000 \AA$ is
(a) $9: 4$
(b) $3: 2$
(c) $16: 81$
(d) $8: 27$
[2017]
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Answer:
Correct Answer: 28. (b)
Solution:
- (b) Resolving power of a microscope $=\frac{2 \mu \sin \theta}{\lambda}$
i.e., $R \propto \frac{1}{\lambda} \quad$ or, $\frac{R_1}{R_2}=\frac{\lambda_2}{\lambda_1}$
Given that the two wavelengths,
$\lambda_1=4000 \AA$ and $\lambda_2=6000 \AA$
$\therefore \frac{R_1}{R_2}=\frac{6000 \AA}{4000 \AA}=\frac{3}{2}$
