Thermodynamics - Result Question 6
6. 110 joules of heat is added to a gaseous system whose internal energy is $40 J$. Then the amount of external work done is
(a) $150 J$
(b) $70 J$
(c) $110 J$
(d) $40 J$
[1993]
Show Answer
Answer:
Correct Answer: 6. (b)
Solution:
- (b) $\Delta Q=\Delta U+\Delta W$
$\Rightarrow \Delta W=\Delta Q-\Delta U=110-40=70 J$
