SATHEE: Thermodynamics - Result Question 4

Thermodynamics - Result Question 4

4. An ideal gas goes from state $A$ to state $B$ via three different processes as indicated in the $P - V$ diagram:

[2012M]

If $Q_{1}, Q_{2}, Q_{3}$ indicate the heat a absorbed by the gas along the three processes and $Δ U_{1}, Δ U_{2}$ , $Δ U_{3}$ indicate the change in internal energy along the three processes respectively, then

(a) $Q_{1} > Q_{2} > Q_{3}$ and $Δ U_{1} = Δ U_{2} = Δ U_{3}$

(b) $Q_{3} > Q_{2} > Q_{1}$ and $Δ U_{1} = Δ U_{2} = Δ U_{3}$

(d) $Q_{3} > Q_{2} > Q_{1}$ and $Δ U_{1} > Δ U_{2} > Δ U_{3}$

Show Answer

Answer:

Correct Answer: 4. (a)

Solution:

(a) Initial and final condition is same for all process

$Δ U_{1} = Δ U_{2} = Δ U_{3}$

from first law of thermodynamics

$Δ Q = Δ U + Δ W$

Work done

$Δ W_{1} > Δ W_{2} > Δ W_{3}$ (Area of P.V. graph)

So $Δ Q_{1} > Δ Q_{2} > Δ Q_{3}$

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Thermodynamics - Result Question 4

4. An ideal gas goes from state A to state B via three different processes as indicated in the P−V diagram:

Answer:

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4. An ideal gas goes from state $A$ to state $B$ via three different processes as indicated in the $P - V$ diagram: