SATHEE: Thermodynamics - Result Question 34

Thermodynamics - Result Question 34

36. A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are

$P_{A} = 3 \times 10^{4} P a$

$V_{A} = 2 \times 10^{- 3} m^{3}$

$P_{B} = 8 \times 10^{4} P a$

$V_{D} = 5 \times 10^{- 3} m^{3}$ .

In process $A B, 600 J$ of heat is added to the system and in process $B C, 200 J$ of heat is added to the system. The change in internal energy of the system in process $A C$ would be

(a) $560 J$

(b) $800 J$

(d) $640 J$

[1991]

Show Answer

Answer:

Correct Answer: 36. (a)

Solution:

(a) $B C$ is isobaric process,

$\begin{aligned} ∴ W = P_{B} \times (V_{D} - V_{A}) = 240 J \\ Δ Q = 600 + 200 = 800 J \\ Using Δ Q = Δ U + Δ W \\ \Rightarrow Δ U = Δ Q - Δ W = 800 - 240 = 560 J \end{aligned}$

Since $A B$ is an isochoric process i.e., $Δ V = 0$ so, no work is done.

Thermodynamics - Result Question 34

36. A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are

Answer:

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Thermodynamics - Result Question 34

36. A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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