Thermal Properties of Matter - Result Question 7
7. The temperature of inversion of a thermocouple is $620^{\circ} C$ and the neutral temperature is $300^{\circ} C$. What is the temperature of cold junction?
[2005]
(a) $320^{\circ} C$
(b) $20^{\circ} C$
(c) $-20^{\circ} C$
(d) $40^{\circ} C$
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Answer:
Correct Answer: 7. (c)
Solution:
(c) $\theta_n=\frac{\theta_c+\theta_i}{2}$
$\therefore \theta_c=2 \theta_n-\theta_i=2(300)-620=-20^{\circ} C$
