Thermal Properties of Matter - Result Question 33

34. Consider a compound slab consisting of two different materials having equal thicknesses and thermal conductivities K and 2K, respectively. The equivalent thermal conductivity of the slab is

[2003]

(a) 43K

(b) 23K

(c) 3K

(d) 3K

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Answer:

Correct Answer: 34. (a)

Solution:

  1. (a) In series, equivalent thermal conductivity

Keq =2K1K2K1+K2

or, Keq =2×K×2KK+2K=43K

In electricity equivalent resistance in series grouping Rs=R1+R2+R3..+Rn

In heat-thermal resistance in series Rsn=R1+R2+ R3..+Rn

1+2+..nKs=1K1A+2K2A+..+nKnA

For n no. of rods of equal length

Ks=n1K1+1K2..+1Kn



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