SATHEE: Thermal Properties of Matter

Thermal Properties of Matter - Result Question 29

30. Assuming the sun to have a spherical outer surface of radius $r$ , radiating like a black body at temperature $t^{\circ} C$ , the power received by a unit surface, (normal to the incident rays) at a distance $R$ from the centre of the sun is [2007]

(a) $\frac{r^{2} σ (t + 273)^{4}}{4 π R^{2}}$

(b) $\frac{16 π^{2} r^{2} σ t^{4}}{R^{2}}$

(d) $\frac{4 π r^{2} σ t}{R^{2}}$

where $σ$ is the Stefan’s constant.

Show Answer

Answer:

Correct Answer: 30. (c)

Solution:

$= σ (t + 273)^{4} 4 π r^{2}$

Power received by a unit surface

$= \frac{σ (t + 273)^{4} 4 π r^{2}}{4 π R^{2}} = \frac{r^{2} σ (t + 273)^{4}}{R^{2}}$

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Thermal Properties of Matter - Result Question 29

30. Assuming the sun to have a spherical outer surface of radius r, radiating like a black body at temperature t∘C, the power received by a unit surface, (normal to the incident rays) at a distance R from the centre of the sun is [2007]

Answer:

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30. Assuming the sun to have a spherical outer surface of radius $r$ , radiating like a black body at temperature $t^{\circ} C$ , the power received by a unit surface, (normal to the incident rays) at a distance $R$ from the centre of the sun is [2007]