SATHEE: Thermal Properties of Matter

Thermal Properties of Matter - Result Question 23

23. A slab of stone of area $0.36 m^{2}$ and thickness $0.1 m$ is exposed on the lower surface to steam at $100^{\circ} C$ . A block of ice at $0^{\circ} C$ rests on the upper surface of the slab. In one hour $4.8 k g$ of ice is melted. The thermal conductivity of slab is :

(Given latent heat of fusion of ice $= 3.36 \times$ $10^{5} J k g^{- 1}$ .) :

[2012M]

(a) $1.24 J / m / s /^{\circ} C$

(b) $1.29 J / m / s /^{\circ} C$

(d) $1.02 J / m / s /^{\circ} C$

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Answer:

Correct Answer: 23. (a)

Solution:

(a) According to condition,

$100^{\circ} C (steam)$

Rate of heat given by steam $=$ Rate of heat taken by ice where $K =$ Thermal conductivity of the slab $m =$ Mass of the ice $L =$ Latent heat of melting/fusion $A =$ Area of the slab

$\frac{d Q}{d t} = \frac{K A (100 - 0)}{1} = m \frac{d L}{d t}$

$\frac{K \times 100 \times 0.36}{0.1} = \frac{4.8 \times 3.36 \times 10^{5}}{60 \times 60}$

$K = 1.24 J / m / s /^{\circ} C$

In electrical conduction

$I = \frac{d q}{d t} = \frac{V_{1} - V_{2}}{R} = \frac{σ A}{ℓ} (V_{1} - V_{2})$

In thermal conduction,

$H = \frac{d θ}{d t} = \frac{θ_{1} - θ_{2}}{R} = \frac{k A}{ℓ} (θ_{1} - θ_{2})$

$K =$ Thermal conductivity of conductor. 25 .

Thermal Properties of Matter - Result Question 23

23. A slab of stone of area $0.36 m^{2}$ and thickness $0.1 m$ is exposed on the lower surface to steam at $100^{\circ} C$ . A block of ice at $0^{\circ} C$ rests on the upper surface of the slab. In one hour $4.8 k g$ of ice is melted. The thermal conductivity of slab is :

Answer:

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Thermal Properties of Matter - Result Question 23

23. A slab of stone of area 0.36m2 and thickness 0.1m is exposed on the lower surface to steam at 100∘C. A block of ice at 0∘C rests on the upper surface of the slab. In one hour 4.8kg of ice is melted. The thermal conductivity of slab is :

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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23. A slab of stone of area $0.36 m^{2}$ and thickness $0.1 m$ is exposed on the lower surface to steam at $100^{\circ} C$ . A block of ice at $0^{\circ} C$ rests on the upper surface of the slab. In one hour $4.8 k g$ of ice is melted. The thermal conductivity of slab is :