SATHEE: System of Particles and Rotational Motion

System of Particles and Rotational Motion - Result Question 85

92. If a sphere is rolling, the ratio of the translational energy to total kinetic energy is given by [1991]

(a) $7 : 10$

(b) $2 : 5$

(d) $5 : 7$

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Answer:

Correct Answer: 92. (d)

Solution:

$\begin{aligned} E & = E_{t} + E_{r} = \frac{1}{2} m v^{2} + \frac{1}{2} I ω^{2} \\ = \frac{1}{2} m v^{2} + \frac{1}{2} \times (\frac{2}{5} m r^{2}) ω^{2} \\ = \frac{1}{2} m v^{2} + \frac{1}{5} m v^{2} = \frac{7}{10} m v^{2} \\ ∴ \frac{E_{t}}{E} & = \frac{\frac{1}{2} m v^{2}}{\frac{7}{10} m v^{2}} = \frac{5}{7} \end{aligned}$

System of Particles and Rotational Motion - Result Question 85

92. If a sphere is rolling, the ratio of the translational energy to total kinetic energy is given by [1991]

Answer:

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System of Particles and Rotational Motion - Result Question 85

92. If a sphere is rolling, the ratio of the translational energy to total kinetic energy is given by [1991]

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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