System of Particles and Rotational Motion - Result Question 82

89. A thin uniform circular ring is rolling down an inclined plane of inclination 30 without slipping. Its linear acceleration along the inclination plane will be

[1994]

(a) g2

(b) g3

(c) g4

(d) 2g3

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Answer:

Correct Answer: 89. (c)

Solution:

  1. (c)

a=gsinθ(1+K2/R2)=gsin301+1=g4



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