System of Particles and Rotational Motion - Result Question 57

61. The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its midpoint and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

(a) $I_0+ML^{2} / 2$

(c) $I_0+2 ML^{2}$

(b) $I_0+ML^{2} / 4$

(d) $I_0+ML^{2}$

[2011]

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Answer:

Correct Answer: 61. (b)

Solution:

  1. (b) By theorem of parallel axes,

$I=I _{cm}+Md^{2}$

$I=I_0+M(L / 2)^{2}=I_0+ML^{2} / 4$



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