System of Particles and Rotational Motion - Result Question 17
17. The angular speed of an engine wheel making 90 revolutions per minute is
(a) $1.5 \pi rad / s$
(b) $3 \pi rad / s$
(c) $4.5 \pi rad / s$
(d) $6 \pi rad / s$
[1995]
Show Answer
Answer:
Correct Answer: 17. (b)
Solution:
- (b) Number of revolutions made by the engine wheel $(n)=90$ per minute.
Angular speed of the engine wheel
$(\omega)=\frac{2 \pi n}{60}=\frac{2 \pi \times 90}{60}=3 \pi rad / s$.
