System of Particles and Rotational Motion - Result Question 10
10. In carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance $1.12 \times 10^{-10} m$. The distance of the centre of mass, from the carbon atom is
(a) $0.64 \times 10^{-10} m$
(b) $0.56 \times 10^{-10} m$
(c) $0.51 \times 10^{-10} m$
(d) $0.48 \times 10^{-10} m$
[1997]
Topic 2: Angular Displacement, Velocity and Acceleration
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Answer:
Correct Answer: 10. (a)
Solution:
From definition of centre of mass.
$ \begin{aligned} d & =\frac{16 \times 1.12 \times 10^{-10}+12 \times 0}{16+12} \\ & =\frac{16 \times 1.12 \times 10^{-10}}{28}=0.64 \times 10^{-10} m . \end{aligned} $
