SATHEE: Semiconductor Electronics Materials Devices and Simple Circuits

Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 19

19. A zener diode, having breakdown voltage equal to $15 V$ , is used in a voltage regulator circuit shown in figure. The current through the diode is

[2011M]

(a) $10 m A$

(b) $15 m A$

(d) $5 m A$

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Answer:

Correct Answer: 19. (d)

Solution:

(d) Voltage across zener diode is constant.

Current in $1 k Ω$ resistor,

(i) $1 k Ω = \frac{15 v o l t}{1 k Ω} = 15 m A$

Current in $250 Ω$ resistor,

$\begin{matrix} (i)_{250 Ω} = \frac{(20 - 15) V}{250 Ω} = \frac{5 V}{250 Ω} \\ = \frac{20}{1000} A = 20 m A \\ ∴ ()_{zener diode} = (20 - 15) = 5 m A . \end{matrix}$

Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 19

19. A zener diode, having breakdown voltage equal to $15 V$ , is used in a voltage regulator circuit shown in figure. The current through the diode is

Answer:

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Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 19

19. A zener diode, having breakdown voltage equal to 15V, is used in a voltage regulator circuit shown in figure. The current through the diode is

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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19. A zener diode, having breakdown voltage equal to $15 V$ , is used in a voltage regulator circuit shown in figure. The current through the diode is