Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 18

18. Pure Si at 500K has equal number of electron (ne) and hole (nh) concentrations of 1.5×1016m3. Doping by indium increases nh to 4.5×1022m3. The doped semiconductor is of

[2011M]

(a) n-type with electron concentration

ne=5×1022m3

(b) p-type with electron concentration

ne=2.5×1010m3

(c) n-type with electron concentration

ne=2.5×1023m3

(d) p-type having electron concentration

ne=5×109m3

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Answer:

Correct Answer: 18. (d)

Solution:

  1. (d) ni2=nenh

(1.5×1016)2=ne(4.5×1022)ne=0.5×1010 or ne=5×109 Given nh=4.5×1022nh»ne

Semiconductor is p-type and

ne=5×109m3.



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