Semiconductor Electronics Materials Devices and Simple Circuits - Result Question 100

102. The circuit

[2008]

is equivalent to

(a) AND gate

(b) NAND gate

(c) NOR gate

(d) OR gate

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Answer:

Correct Answer: 102. (c)

Solution:

  1. (c) Let A and B be inputs and Y the output.

Then Y1=(A+B)=AB

(By De-Morgan’s theorem)

Y2=Y1=(AB)=A+B=A+B

Y=Y2=(A+B)

Hence, the given circuit is equivalent to a NOR gate.

NOR and NAND gates is a universal gates as they can be used to perform the basic logic functions. AND, OR and NOT gate.



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