Physical World Units and Measurements - Result Question 36
38. The dimensional formula for angular momentum is
(a) $[M^{0} L^{2} T^{-2}]$
(c) $[MLT^{-1}]$
(b) $[ML^{2} T^{-1}]$
(d) $[ML^{2} T^{-2}]$
[1988]
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Answer:
Correct Answer: 38. (b)
Solution:
- (b) Angular momentum
$=$ Momentum of inertia $\times$ Angular velocity
So dimensional formula,
$=[ML^{2}] \times[T^{-1}]$
$=[ML^{2} T^{-1}]$
