Physical World Units and Measurements - Result Question 33
35. The dimensional formula of torque is [1989]
(a) $[ML^{2} T^{-2}]$
(b) $[MLT^{-2}]$
(c) $[ML^{-1} T^{-2}]$
(d) $[ML^{-2} T^{-2}]$
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Answer:
Correct Answer: 35. (a)
Solution:
- (a) $\tau=$ Force $\times$ distance
So dimensional formula,
$ =[MLT^{-2}][L]=[ML^{2} T^{-2}] $
