Physical World Units and Measurements - Result Question 29

31. The dimensional formula for permeability μ is given by

(a) [MLT2A2]

[1991]

(b) [M0L1T]

(c) [M0L2T1A2]

(d) None of the above

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Answer:

Correct Answer: 31. (a)

Solution:

  1. (a) Permeability of free space,

μ0=2π× force × distance ( current )2× length 

So, dimensional formula

μ0=[MLT2][L][A2][L]=[MLT2A2]

Also find the dimensional formula by using the relation,

Speed of light, c=1μ0ε0



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