Physical World Units and Measurements - Result Question 13
13. The dimensions of $(\mu_0 \epsilon_0)^{\frac{-1}{2}}$ are
(a) $[L^{1 / 2} T^{-1 / 2}]$
(b) $[L^{-1} T]$
(c) $[LT^{-1}]$
(d) $[L^{-1 / 2} T^{1 / 2}]$
[2012M, 2011]
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Answer:
Correct Answer: 13. (c)
Solution:
- (c) $(\mu_0 \varepsilon_0)^{-1 / 2}=\frac{1}{\sqrt{\mu_0 \varepsilon_0}} \Rightarrow c=$ speed of light where $\varepsilon_0=$ permittivity of free space
$\mu_0=$ permeability of free space
So dimensions of $(\mu_0 \varepsilon_0)^{-1 / 2}$ will be $[LT^{-1}]$
