Oscillations - Result Question 52
56. The time period of a simple pendulum is 2 seconds. If its length is increased by 4-times, then its period becomes
(a) $16 s$
(b) $12 s$
(c) $8 s$
(d) $4 s$
[1999]
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Answer:
Correct Answer: 56. (d)
Solution:
(d) $T=2 \pi \sqrt{\frac{\ell}{g}} \quad T \propto \sqrt{\ell}$
If $\ell$ is increased by 4 times, time period will increase by two times.
