Oscillations - Result Question 51

55. Masses MA and MB hanging from the ends of strings of lengths LA and LB are executing simple harmonic motions. If their frequencies are fA= 2fB, then

(a) LA=2LB and MA=MB/2

[2000]

(b) LA=4LB regardless of masses

(c) LA=LB/4 regardless of masses

(d) LA=2LB and MA=2MB

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Answer:

Correct Answer: 55. (c)

Solution:

(c) fA=12πgLA

and fB=fA2=12πgLB

fAfA/2=12πgLA×2πLBg

2=LBLA4=LBLA,

regardless of mass.



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