Oscillations - Result Question 5

6. When two displacements represented by $y_1=a \sin (\omega t)$ and $y_2=b \cos (\omega t)$ are superimposed the motion is:

[2015]

(a) simple harmonic with amplitude $\frac{a}{b}$

(b) simple harmonic with amplitude $\sqrt{a^{2}+b^{2}}$

(c) simple harmonic with amplitude $\frac{(a+b)}{2}$

(d) not a simple harmonic

Show Answer

Answer:

Correct Answer: 6. (b)

Solution:

  1. (b) The two displacements equations are $y_1=a \sin (\omega t)$

$ \begin{aligned} & \text{ and } y_2=b \cos (\omega t)=b \sin (\omega t+\frac{\pi}{2}) \\ & \begin{matrix} y _{eq}=y_1+y_2 \\ \quad=a \sin \omega t+b \cos \omega t \end{matrix} \end{aligned} $

$ =a \sin \omega t+b \sin (\omega t+\frac{\pi}{2}) $

Since the frequencies for both SHMs are same, resultant motion will be SHM.

Now amplitude, $A _{e q}=\sqrt{a^{2}+b^{2}+2 a b \cos \frac{\pi}{2}}$

$ \Rightarrow A _{e q}=\sqrt{a^{2}+b^{2}} $



NCERT Chapter Video Solution

Dual Pane