SATHEE: Oscillations - Result Question 42

Oscillations - Result Question 42

46. A block of mass $M$ is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value $k$ . The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be:

(a) $2 M g / k$

(b) $4 M g / k$

(d) $M g / k$

[2009]

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Answer:

Correct Answer: 46. (d)

Solution:

(d) Restoring force, $f^{'} = - k x$

where $x$ is the extension produced in the spring.

Weight of the mass acting downward $= M g$ .

In equilibrium

$k x = M g$ or $x = \frac{M g}{k}$

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Oscillations - Result Question 42

46. A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value k. The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be:

Answer:

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46. A block of mass $M$ is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value $k$ . The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be: