Oscillations - Result Question 41

45. A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T. The speed of the pendulum at x=a2 will be:

[2009]

(a) πaT

(b) 3π2aT

(c) πa3T

(d) πa32T

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Answer:

Correct Answer: 45. (c)

Solution:

(c) Speed v=ωa2x2,x=a2

v=ωa2a24=ω3a24=2πTa32=πa3T



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