SATHEE: Oscillations - Result Question 38

Oscillations - Result Question 38

43. A particle is executing a simple harmonic motion. Its maximum acceleration is a and maximum velocity is $b$ .

[2015 RS]

Then its time period of vibration will be :

(a) $\frac{α}{β}$

(b) $\frac{β^{2}}{α}$

(d) $\frac{β^{2}}{α^{2}}$

Show Answer

Answer:

Correct Answer: 43. (c)

Solution:

When they are connected in series

$\frac{1}{k^{'}} = \frac{1}{6 k} + \frac{1}{3 k} + \frac{1}{2 k}$

$\Rightarrow \frac{1}{k^{'}} = \frac{6}{6 k}$

$∴$ Force constant $k^{'} = k$

And when they are connected in parallel $k^{''} = 6 k + 3 k + 2 k$

$\Rightarrow k^{''} = 11 k$

Then the ratios

$\frac{k^{'}}{k^{''}} = \frac{1}{11}$ i.e., $k^{'} : k^{''} = 1 : 11$

If a spring of force constant $K$ is divided into $n$ equal parts then spring constant of each part will become $n k$ and if these $n$ parts connected in parallel then $k_{eff} = n^{2} k$ .

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Oscillations - Result Question 38

43. A particle is executing a simple harmonic motion. Its maximum acceleration is a and maximum velocity is b.

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

43. A particle is executing a simple harmonic motion. Its maximum acceleration is a and maximum velocity is $b$ .