SATHEE: Oscillations - Result Question 31

Oscillations - Result Question 31

34. A linear harmonic oscillator of force constant $2 \times 10^{6} N / m$ and amplitude $0.01 m$ has a total mechanical energy of $160 J$ . Its

[1996]

(a) potential energy is $160 J$

(b) potential energy is $100 J$

(d) potential energy is $120 J$

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Answer:

Correct Answer: 34. (b)

Solution:

(b) Force constant $k = 2 \times 10^{6} N / m$

Amplitude $(x) = 0.01 m$

Potential Energy $= \frac{1}{2} k x^{2}$

$= \frac{1}{2} \times (2 \times 10^{6}) \times (0.01)^{2} = 100 J$

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Oscillations - Result Question 31

34. A linear harmonic oscillator of force constant 2×106N/m and amplitude 0.01m has a total mechanical energy of 160J. Its

Answer:

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34. A linear harmonic oscillator of force constant $2 \times 10^{6} N / m$ and amplitude $0.01 m$ has a total mechanical energy of $160 J$ . Its