Oscillations - Result Question 28

31. A particle is executing a simple harmonic motion of amplitude ’ a ‘. Its potential energy is maximum when the displacement from the position of the maximum kinetic energy is

[2002]

(a) 0

(b) ±a

(c) ±a/2

(d) a/2

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Answer:

Correct Answer: 31. (b)

Solution:

  1. (b) P.E. of particle executing S.H.M.

=12mω2x2

At x=a, P.E. is maximum i.e. =12mω2a2

K.E. =12mω2(a2x2)

At x=0, K.E. is maximum. Hence, displacement from position of maximum Kinetic energy =±a.



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