Oscillations - Result Question 27
30. The potential energy of a simple harmonic oscillator when the particle is half way to its end point is
[2003]
(a) $\frac{1}{2} E$
(b) $\frac{2}{3} E$
(c) $\frac{1}{8} E$
(d) $\frac{1}{4} E$
where $E$ is the total energy
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Answer:
Correct Answer: 30. (d)
Solution:
(d) $P . E .=\frac{1}{2} k x^{2}=E$
At half way
P.E. $=\frac{1}{2} k(\frac{x}{2})^{2}=\frac{\frac{1}{2} k x^{2}}{4}=\frac{E}{4}$
