Oscillations - Result Question 17
20. A particle executing S.H.M. has amplitude $0.01 m$ and frequency $60 Hz$. The maximum acceleration of the particle is
(a) $144 \pi^{2} m / s^{2}$
(c) $80 \pi^{2} m / s^{2}$
(b) $120 \pi^{2} m / s^{2}$
(d) $60 \pi^{2} m / s^{2}$
[1999]
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Answer:
Correct Answer: 20. (a)
Solution:
- (a) Amplitude $(A)=0.01 m$, Frequency $=60 Hz$ Maximum acceleration
$=A \omega^{2}=0.01 \times(2 \pi n)^{2}$
$=0.01 \times 4 \pi^{2} \times 60 \times 60=144 \pi^{2} m / sec^{2}$
