Oscillations - Result Question 14

17. A particle executing simple harmonic motion of amplitude $5 cm$ has maximum speed of $31.4 cm / s$. Its oscillation per second

(a) 4

(b) 3

(c) 2

(d) 1

[2005]

Show Answer

Answer:

Correct Answer: 17. (d)

Solution:

  1. (d) In S.H.M., $v _{\max }=A \omega=A(2 \pi f)$

$f=\frac{v _{\max }}{2 \pi A}=\frac{31.4}{2(3.14) \times 5}=1$ oscillation per sec.



NCERT Chapter Video Solution

Dual Pane