Nuclei - Result Question 96
99. An element $A$ decays into element $C$ by a two step process
$A \to B+ _2 He^{4}$
$B \to C+2 e^{-}$
Then
[1989]
(a) $A$ and $C$ are isotopes
(b) $A$ and $C$ are isobars
(c) $A$ and $B$ are isotopes
(d) $A$ and $B$ are isobars
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Answer:
Correct Answer: 99. (a)
Solution:
- (a) From eqn. (ii), B has 2 units of charge more than C.
From eqn. (i), $A$ loses 2 units of charge by emission of alpha particle. Hence,
$A$ and $C$ are isotopes as their charge numbers are same.
