SATHEE: Nuclei - Result Question 96

Nuclei - Result Question 96

99. An element $A$ decays into element $C$ by a two step process

$A \to B +_{2} H e^{4}$

$B \to C + 2 e^{-}$

Then

[1989]

(a) $A$ and $C$ are isotopes

(b) $A$ and $C$ are isobars

(d) $A$ and $B$ are isobars

Show Answer

Answer:

Correct Answer: 99. (a)

Solution:

(a) From eqn. (ii), B has 2 units of charge more than C.

From eqn. (i), $A$ loses 2 units of charge by emission of alpha particle. Hence,

$A$ and $C$ are isotopes as their charge numbers are same.

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Nuclei - Result Question 96

99. An element A decays into element C by a two step process

Answer:

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99. An element $A$ decays into element $C$ by a two step process