Nuclei - Result Question 4

4. If the nucleus 1327Al has nuclear radius of about 3.6fm, then 32125Te would have its radius approximately as

[2007]

(a) 9.6fm

(b) 12.0fm

(c) 4.8fm

(d) 6.0fm.

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Answer:

Correct Answer: 4. (d)

Solution:

  1. (d) It has been known that a nucleus of mass number A has radius

R=R0A1/3,

where R0=1.2×1015m

and A= mass number

In case of 1327A, let nuclear radius be R1

and for 32125Te, nuclear radius be R2

For 1327Al,R1=R0(27)1/3=3R0

For 32125Te,R2=R0(125)1/3=5R0

R2R1=5R03R0=53R1=53×3.6=6fm



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